I am doing online classes for my school and i have been stuck on this question for weeks and i need help fast
This is a triangle

2 thoughts on “Angle A is 85 degrees and Angle B is 78 degrees the distance between Angle B and Angle C is 269 feet what is t?”

Andy

is this a triangle? between which two angles is t located?

Chuck U. Farley

The angles of all triangle sum to 180Â°. So you know C is

C = 180Â° – 85Â° – 78Â° = 17Â°

All the lengths can be calculated by forming a right triangle “inside” the triangle ABC. Draw a line CD, where D lies on line AB, and CD is perpendicular to AB. The length of CD is

CD = 269sin(78Â°)

For side AC:

sin(85Â°) = CD/AC
AC = CD/sin(85Â°)
AC = 269sin(78Â°)/sin(85Â°)
AC ? 269(.98188)
AC ? 264.1 feet

Likewise, for side AB

AB = 269sin(17Â°)/sin(85Â°)
AB ? 269(.29349)
AB ? 78.9 feet

is this a triangle? between which two angles is t located?

The angles of all triangle sum to 180Â°. So you know C is

C = 180Â° – 85Â° – 78Â° = 17Â°

All the lengths can be calculated by forming a right triangle “inside” the triangle ABC. Draw a line CD, where D lies on line AB, and CD is perpendicular to AB. The length of CD is

CD = 269sin(78Â°)

For side AC:

sin(85Â°) = CD/AC

AC = CD/sin(85Â°)

AC = 269sin(78Â°)/sin(85Â°)

AC ? 269(.98188)

AC ? 264.1 feet

Likewise, for side AB

AB = 269sin(17Â°)/sin(85Â°)

AB ? 269(.29349)

AB ? 78.9 feet