Angle A is 85 degrees and Angle B is 78 degrees the distance between Angle B and Angle C is 269 feet what is t?

By | September 4, 2015

I am doing online classes for my school and i have been stuck on this question for weeks and i need help fast
This is a triangle

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2 thoughts on “Angle A is 85 degrees and Angle B is 78 degrees the distance between Angle B and Angle C is 269 feet what is t?

  1. Chuck U. Farley

    The angles of all triangle sum to 180°. So you know C is

    C = 180° – 85° – 78° = 17°

    All the lengths can be calculated by forming a right triangle “inside” the triangle ABC. Draw a line CD, where D lies on line AB, and CD is perpendicular to AB. The length of CD is

    CD = 269sin(78°)

    For side AC:

    sin(85°) = CD/AC
    AC = CD/sin(85°)
    AC = 269sin(78°)/sin(85°)
    AC ? 269(.98188)
    AC ? 264.1 feet

    Likewise, for side AB

    AB = 269sin(17°)/sin(85°)
    AB ? 269(.29349)
    AB ? 78.9 feet

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